Remove PERL_BOOL_AS_CHAR uses; always define HAS_BOOL

Now that C99 is required, bool is always defined, so HAS_BOOL should
also always be defined.

PERL_BOOL_AS_CHAR was used to workaround problems when no bool type
existed, so it is obsolete, and in fact perl won't compile if
PERL_BOOL_AS_CHAR is #defined.  So remove it completely from being
looked at.

1 files changed, 0 insertions, 3 deletions

diff --git a/perl.c b/perl.c
index 1edeb3548e..3f3cab15de 100644
--- a/perl.c
+++ b/perl.c
@@ -1906,9 +1906,6 @@ S_Internals_V(pTHX_ CV *cv)
 #  ifdef NO_TAINT_SUPPORT
                              " NO_TAINT_SUPPORT"
 #  endif
-#  ifdef PERL_BOOL_AS_CHAR
-                             " PERL_BOOL_AS_CHAR"
-#  endif
 #  ifdef PERL_COPY_ON_WRITE
                              " PERL_COPY_ON_WRITE"
 #  endif