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| author | gfyoung <gfyoung17@gmail.com> | 2015-12-19 16:49:35 -0800 |
|---|---|---|
| committer | gfyoung <gfyoung17@gmail.com> | 2015-12-19 16:50:09 -0800 |
| commit | 8bc592fabf4a2b0bc76db996b1523330ba095be3 (patch) | |
| tree | c8a1a549e5a093a9433fe9a50a6e0e8bb5358ab1 /numpy/lib/financial.py | |
| parent | e2bdaccba1a8691f9223b059b981b2890bb13b09 (diff) | |
| download | numpy-8bc592fabf4a2b0bc76db996b1523330ba095be3.tar.gz | |
DOC: Use print only as function when print_function is imported from __future__
Closes gh-6863.
Diffstat (limited to 'numpy/lib/financial.py')
| -rw-r--r-- | numpy/lib/financial.py | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/numpy/lib/financial.py b/numpy/lib/financial.py index a7e4e60b6..c42424da1 100644 --- a/numpy/lib/financial.py +++ b/numpy/lib/financial.py @@ -247,7 +247,7 @@ def nper(rate, pmt, pv, fv=0, when='end'): If you only had $150/month to pay towards the loan, how long would it take to pay-off a loan of $8,000 at 7% annual interest? - >>> print round(np.nper(0.07/12, -150, 8000), 5) + >>> print(round(np.nper(0.07/12, -150, 8000), 5)) 64.07335 So, over 64 months would be required to pay off the loan. @@ -347,7 +347,7 @@ def ipmt(rate, per, nper, pv, fv=0.0, when='end'): >>> for payment in per: ... index = payment - 1 ... principal = principal + ppmt[index] - ... print fmt.format(payment, ppmt[index], ipmt[index], principal) + ... print(fmt.format(payment, ppmt[index], ipmt[index], principal)) 1 -200.58 -17.17 2299.42 2 -201.96 -15.79 2097.46 3 -203.35 -14.40 1894.11 |