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author | David Beazley <dave@dabeaz.com> | 2020-06-18 15:04:22 -0500 |
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committer | GitHub <noreply@github.com> | 2020-06-18 15:04:22 -0500 |
commit | a00c1c9186a99c06e07986811ae5c5ab5b5c4659 (patch) | |
tree | 6d84d68b79cbbb235f2a18c53d8757c63bce7b4d | |
parent | 83c5b91972a0905d620f3407e7d37f4cbcfe4178 (diff) | |
parent | 33f7a5728a07a2f226596c2959fbb223edcc16e8 (diff) | |
download | ply-a00c1c9186a99c06e07986811ae5c5ab5b5c4659.tar.gz |
Merge pull request #238 from paulsmith/patch-1
docs: minor update for Python3
-rw-r--r-- | docs/ply.rst | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/docs/ply.rst b/docs/ply.rst index 2167398..600ed6d 100644 --- a/docs/ply.rst +++ b/docs/ply.rst @@ -501,7 +501,7 @@ it can continue to parse. Here is an example of how this works:: # EOF handling rule def t_eof(t): # Get more input (Example) - more = raw_input('... ') + more = input('... ') if more: self.lexer.input(more) return self.lexer.token() @@ -1318,7 +1318,7 @@ as previously described. Here is how you would do it with while True: try: - s = raw_input('calc > ') + s = input('calc > ') except EOFError: break if not s: continue |